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Statement List for Metamath Proof Explorer - 3901-4000 - Page 40 of 108
TypeLabelDescription
Statement
 
Theoremisofr 3901 An isomorphism preserves foundedness. Proposition 6.32(1) of [TakeutiZaring] p. 33.
|- (H Isom R, S (A, B) -> (R Fr A <-> S Fr B))
 
Theoremisowe 3902 An isomorphism preserves well ordering. Proposition 6.32(3) of [TakeutiZaring] p. 33.
|- (H Isom R, S (A, B) -> (R We A <-> S We B))
 
Theoremf1oiso 3903 Any one-to-one onto function determines an isomorphism with an induced relation S. Proposition 6.33 of [TakeutiZaring] p. 34.
|- ((H:A-1-1-onto->B /\ S = {<.z, w>. | E.x e. A E.y e. A ((z = (H` x) /\ w = (H` y)) /\ xRy)}) -> H Isom R, S (A, B))
 
Theoremf1owe 3904 Well-ordering of isomorphic relations.
|- R = {<.x, y>. | (F` x)S(F` y)}   =>   |- (F:A-1-1-onto->B -> (S We B -> R We A))
 
Theoremf1oweALT 3905 Well-ordering of isomorphic relations. (This version is proved directly instead of wit the isomorphism predicate.)
|- R = {<.x, y>. | (F` x)S(F` y)}   =>   |- (F:A-1-1-onto->B -> (S We B -> R We A))
 
Cantor's Theorem
 
Theoremcanth 3906 No set A is equinumerous to its power set (Cantor's theorem), i.e. no function can map A it onto its power set. Compare Theorem 6B(b) of [Enderton] p. 132. For the equinumerosity version, see canth2 4479. Note that A must be a set: this theorem does not hold when A is too large to be a set; see ncanth 3907 for a counterexample. (Use nex 1101 if you want the form -. E.ff:A-onto->P~A.)
|- A e. V   =>   |- -. F:A-onto->P~A
 
Theoremncanth 3907 Cantor's theorem fails for the universal class (which is not a set but a proper class by nvelv 2712). Specifically, the identity function maps the universe onto its power class. Compare canth 3906 that works for sets. See also the remark in ru 1937 about NF, in which Cantor's theorem fails for sets that are "too large." This theorem gives some intuition behind that failure: in NF the universal class is a set, and it equals its own power set.
|- I:V-onto->P~V
 
Miscellaneous ordinal theorems (that depend on functions and relations)
 
Theoremiunon 3908 The indexed union of a set of ordinal numbers B(x) is an ordinal number.
|- A e. V   &   |- B e. V   =>   |- (A.x e. A B e. On -> U_x e. A B e. On)
 
Theoremiinon 3909 The nonempty indexed intersection of a class of ordinal numbers B(x) is an ordinal number.
|- B e. V   =>   |- ((A.x e. A B e. On /\ A =/= (/)) -> |^|_x e. A B e. On)
 
Transfinite recursion
 
Theoremtfrlem1 3910 A technical lemma for transfinite recursion. Compare Lemma 1 of [TakeutiZaring] p. 47.
|- (A e. On -> ((F Fn A /\ G Fn A) -> (A.x e. A ((F` x) = (B` (F |` x)) /\ (G` x) = (B` (G |` x))) -> A.x e. A (F` x) = (G` x))))
 
Theoremtfrlem2 3911 Lemma for transfinite recursion. This provides some messy details needed to link tfrlem1 3910 into the main proof.
 
Theoremtfrlem3 3912 Lemma for transfinite recursion. Let A be the class of "acceptable" functions. The final thing we're interested in is the union of all these acceptable functions. This lemma just changes some bound variables in A for later use.
 
Theoremtfrlem4 3913 Lemma for transfinite recursion. A is the class of all "acceptable" functions, and F is their union. First we show that an acceptable function is in fact a function.
 
Theoremtfrlem5 3914 Lemma for transfinite recursion. The values of two acceptable functions are the same within their domains.
 
Theoremtfrlem6 3915 Lemma for transfinite recursion. The union of all acceptable functions is a relation.
 
Theoremtfrlem7 3916 Lemma for transfinite recursion. The union of all acceptable functions is a function.
 
Theoremtfrlem8 3917 Lemma for transfinite recursion. The domain of F is ordinal. (The proof was shortened by Alan Sare, 11-Mar-2008.)
 
Theoremtfrlem9 3918 Lemma for transfinite recursion. Here we compute the value of F (the union of all acceptable functions).
 
Theoremtfrlem10 3919 Lemma for transfinite recursion. We define class C by extending F with one ordered pair. We will assume, falsely, that domain of F is a member of, and thus not equal to, On. Using this assumption we will prove facts about C that will lead to a contradiction in tfrlem13 3922, thus showing the domain of F does in fact equal On. Here we show (under the false assumption) that C is a function extending the domain of F by one. (The proof was shortened by Alan Sare, 20-Feb-2008.)
 
Theoremtfrlem11 3920 Lemma for transfinite recursion. Compute the value of C.
 
Theoremtfrlem12 3921 Lemma for transfinite recursion. Show C is an acceptable function.
 
Theoremtfrlem13 3922 Lemma for transfinite recursion. If dom F is in On, then C is acceptable, and thus a subset of F, but dom C is bigger than dom F. This is a contradiction, so dom F must be On.
 
Theoremtfr1 3923 Principle of Transfinite Recursion, part 1 of 3. Theorem 7.41(1) of [TakeutiZaring] p. 47. We start with an arbitrary class G, normally a function, and define a class A of all "acceptable" functions. The final function we're interested in is the union F of them. F is then said to be defined by transfinite recursion. The purpose of the 3 parts of this theorem is to demonstrate properties of F. In this first part we show that F is a function whose domain is all ordinal numbers.
|- A = {f | E.x e. On (f Fn x /\ A.y e. x (f` y) = (G` (f |` y)))}   &   |- F = U.A   =>   |- F Fn On
 
Theoremtfr2 3924 Principle of Transfinite Recursion, part 2 of 3. Theorem 7.41(2) of [TakeutiZaring] p. 47. Here we show that the function F has the property that for any function G whatsoever, the "next" value of F is G recursively applied to all "previous" values of F.
|- A = {f | E.x e. On (f Fn x /\ A.y e. x (f` y) = (G` (f |` y)))}   &   |- F = U.A   =>   |- (z e. On -> (F` z) = (G` (F |` z)))
 
Theoremtfr3 3925 Principle of Transfinite Recursion, part 3 of 3. Theorem 7.41(3) of [TakeutiZaring] p. 47. Finally we show that F is unique. We do this by showing that any class B with the same properties of F that we showed in parts 1 and 2 is identical to F.
|- A = {f | E.x e. On (f Fn x /\ A.y e. x (f` y) = (G` (f |` y)))}   &   |- F = U.A   =>   |- ((B Fn On /\ A.x e. On (B` x) = (G` (B |` x))) -> B = F)
 
Theoremtz7.44lem1 3926 G is a function. Lemma for tz7.44-1 3927, tz7.44-2 3928, and tz7.44-3 3929.
|- G = {<.x, y>. | ((x = (/) /\ y = A) \/ (-. (x = (/) \/ Lim dom x) /\ y = (H` (x` U.dom x))) \/ (Lim dom x /\ y = U.ran x))}   =>   |- Fun G
 
Theoremtz7.44-1 3927 The value of F at (/). Part 1 of Theorem 7.44 of [TakeutiZaring] p. 49.
|- G = {<.x, y>. | ((x = (/) /\ y = A) \/ (-. (x = (/) \/ Lim dom x) /\ y = (H` (x` U.dom x))) \/ (Lim dom x /\ y = U.ran x))}   &   |- F Fn On   &   |- (x e. On -> (F` x) = (G` (F |` x)))   &   |- A e. V   =>   |- (F` (/)) = A
 
Theoremtz7.44-2 3928 The value of F at a successor ordinal. Part 2 of Theorem 7.44 of [TakeutiZaring] p. 49.
|- G = {<.x, y>. | ((x = (/) /\ y = A) \/ (-. (x = (/) \/ Lim dom x) /\ y = (H` (x` U.dom x))) \/ (Lim dom x /\ y = U.ran x))}   &   |- F Fn On   &   |- (x e. On -> (F` x) = (G` (F |` x)))   &   |- B e. On   =>   |- (F` suc B) = (H` (F` B))
 
Theoremtz7.44-3 3929 The value of F at a limit ordinal. Part 3 of Theorem 7.44 of [TakeutiZaring] p. 49.
|- G = {<.x, y>. | ((x = (/) /\ y = A) \/ (-. (x = (/) \/ Lim dom x) /\ y = (H` (x` U.dom x))) \/ (Lim dom x /\ y = U.ran x))}   &   |- F Fn On   &   |- (x e. On -> (F` x) = (G` (F |` x)))   &   |- B e. On   =>   |- (Lim B -> (F` B) = U.(F"B))
 
Recursive definition generator
 
Syntaxcrdg 3930 Extend class notation with the recursive definition generator.
class rec(A, B)
 
Definitiondf-rdg 3931 Define a recursive definition generator on On (the class of ordinal numbers) with characteristic function F and initial value A. This combines functions F in tfr1 3923 and G in tz7.44-1 3927 into one definition. This rather amazing operation allows us to define, with compact direct definitions, functions that are usually defined in textbooks only with indirect self-referencing recursive definitions. A recursive definition requires advanced metalogic to justify - in particular, eliminating a recursive definition is very difficult and often not even shown in textbooks. On the other hand, the elimination of a direct definition is a matter of simple mechanical substitution. The price paid is the daunting complexity of our rec operation. But once we get past this hurdle, otherwise recursive definitions become relatively simple, as in for example oav 4149, from which we prove the recursive textbook definition as theorems oa0 4154, oasuc 4162, and oalim 4166 (with the help of theorems rdg0 3940, rdgsuc 3941, and rdglim 3942). We can also restrict the rec operation to define otherwise recursive functions on the natural numbers om; see fr0t 3951 and frsuct 3952. Our rec operation apparently does not appear in published literature, although closely related is Definition 25.2 of [Quine] p. 177, which he uses to "turn...a recursion into a genuine or direct definition" (p. 174). Note that the if operators (see df-if 2361) select cases based on whether the domain of g is zero, a successor, or a limit ordinal.

An important use of this definition is in the recursive sequence generator df-seq1 6283 on the natural numbers (as a subset of the complex numbers), allowing us to define, with direct definitions, recursive infinite sequences such as the factorial function df-fac 6903 and integer powers df-exp 6542.

Note: We introduce rec with the philosophical goal of being able to eliminate all definitions with direct mechanical substitution and to verify easily the soundness of definitions. Metamath itself has no built-in technical limitation that prevents recursive definitions in the traditional textbook style.

|- rec(F, A) = U.{f | E.x e. On (f Fn x /\ A.y e. x (f` y) = ({<.g, z>. | z = if(g = (/), A, if(Lim dom g, U.ran g, (F` (g` U.dom g))))}` (f |` y)))}
 
Theoremdfrdg2 3932 Alternate definition of a recursive definition generator. (This was the original definition, but it was later replaced with the slightly shorter df-rdg 3931.)
|- rec(F, A) = U.{f | E.x e. On (f Fn x /\ A.y e. x (f` y) = ({<.g, z>. | ((g = (/) /\ z = A) \/ (-. (g = (/) \/ Lim dom g) /\ z = (F` (g` U.dom g))) \/ (Lim dom g /\ z = U.ran g))}` (f |` y)))}
 
Theoremrdgeq1 3933 Equality theorem for the recursive definition generator.
|- (F = G -> rec(F, A) = rec(G, A))
 
Theoremrdgeq2 3934 Equality theorem for the recursive definition generator.
|- (A = B -> rec(F, A) = rec(F, B))
 
Theoremhbrdg 3935 Bound-variable hypothesis builder for the recursive definition generator.
|- (y e. F -> A.x y e. F)   &   |- (y e. A -> A.x y e. A)   =>   |- (y e. rec(F, A) -> A.x y e. rec(F, A))
 
Theoremrdglem1 3936 Lemma used with the recursive definition generator. This is a trivial lemma that just changes bound variables for later use.
|- {f | E.x e. On (f Fn x /\ A.y e. x (f` y) = (G` (f |` y)))} = {g | E.z e. On (g Fn z /\ A.w e. z (g` w) = (G` (g |` w)))}
 
Theoremrdglem2 3937 Lemma used with the recursive definition generator. This is a trivial lemma that just changes bound variables for later use.
|- {<.x, y>. | ((x = (/) /\ y = A) \/ (-. (x = (/) \/ Lim dom x) /\ y = (H` (x` U.dom x))) \/ (Lim dom x /\ y = U.ran x))} = {<.z, y>. | ((z = (/) /\ y = A) \/ (-. (z = (/) \/ Lim dom z) /\ y = (H` (z` U.dom z))) \/ (Lim dom z /\ y = U.ran z))}
 
Theoremrdgfnon 3938 The recursive definition generator is a function on ordinal numbers.
|- rec(F, A) Fn On
 
Theoremrdgval 3939 Value of the recursive definition generator.
|- (g e. On -> (rec(F, A)` g) = ({<.w, z>. | ((w = (/) /\ z = A) \/ (-. (w = (/) \/ Lim dom w) /\ z = (F` (w` U.dom w))) \/ (Lim dom w /\ z = U.ran w))}` (rec(F,