mmtheorems45 - Metamath Proof Explorer

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Statement List for Metamath Proof Explorer - 4401-4500 - Page 45 of 108

Type	Label	Description
Statement
Theorem	en3d 4401	Equinumerosity inference from an implicit one-to-one onto function.
|- (ph -> A e. V)   &   |- (ph -> (x e. A -> C e. B))   &   |- (ph -> (y e. B -> D e. A))   &   |- (ph -> ((x e. A /\ y e. B) -> (x = D <-> y = C)))   =>   |- (ph -> A ~~ B)
Theorem	en2 4402	Equinumerosity inference from an implicit one-to-one onto function.
|- A e. V   &   |- (x e. A -> C e. V)   &   |- (y e. B -> D e. V)   &   |- ((x e. A /\ y = C) <-> (y e. B /\ x = D))   =>   |- A ~~ B
Theorem	en3 4403	Equinumerosity inference from an implicit one-to-one onto function.
|- A e. V   &   |- (x e. A -> C e. B)   &   |- (y e. B -> D e. A)   &   |- ((x e. A /\ y e. B) -> (x = D <-> y = C))   =>   |- A ~~ B
Theorem	dom2d 4404	A mapping (first hypothesis) that is one-to-one (second hypothesis) implies its domain is dominated by its range.
|- (ph -> (x e. A -> C e. B))   &   |- (ph -> ((x e. A /\ y e. A) -> (C = D <-> x = y)))   =>   |- (ph -> (A e. R -> A ~<_ B))
Theorem	dom2 4405	A mapping (first hypothesis) that is one-to-one (second hypothesis) implies its domain is dominated by its range. C and D can be read C(x) and D(y), as can be shown from their distinct variable conditions.
|- (x e. A -> C e. B)   &   |- ((x e. A /\ y e. A) -> (C = D <-> x = y))   =>   |- (A e. R -> A ~<_ B)
Theorem	idssen 4406	Equality implies equinumerosity.
|- I (_ ~~
Theorem	dmen 4407	The domain of equinumerosity.
|- dom ~~ = V
Theorem	ssdomg 4408	A set dominates its subsets. Theorem 16 of [Suppes] p. 94.
|- (A e. C -> (A (_ B -> A ~<_ B))
Theorem	ssdom2g 4409	A set dominates its subsets. Theorem 16 of [Suppes] p. 94.
|- (B e. C -> (A (_ B -> A ~<_ B))
Theorem	ener 4410	Equinumerosity is an equivalence relation.
|- Er ~~
Theorem	ensymg 4411	Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92.
|- (B e. C -> (A ~~ B -> B ~~ A))
Theorem	ensym 4412	Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92.
|- B e. V   =>   |- (A ~~ B -> B ~~ A)
Theorem	ensymi 4413	Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92.
|- B e. V   &   |- A ~~ B   =>   |- B ~~ A
Theorem	entrt 4414	Transitivity of equinumerosity. Theorem 3 of [Suppes] p. 92.
|- ((A ~~ B /\ B ~~ C) -> A ~~ C)
Theorem	domtr 4415	Transitivity of dominance relation. Theorem 17 of [Suppes] p. 94.
|- ((A ~<_ B /\ B ~<_ C) -> A ~<_ C)
Theorem	entr 4416	A chained equinumerosity inference.
|- A ~~ B   &   |- B ~~ C   =>   |- A ~~ C
Theorem	entr2 4417	A chained equinumerosity inference.
|- C e. V   &   |- A ~~ B   &   |- B ~~ C   =>   |- C ~~ A
Theorem	entr3 4418	A chained equinumerosity inference.
|- B e. V   &   |- A ~~ B   &   |- A ~~ C   =>   |- B ~~ C
Theorem	entr4 4419	A chained equinumerosity inference.
|- B e. V   &   |- A ~~ B   &   |- C ~~ B   =>   |- A ~~ C
Theorem	endomtr 4420	Transitivity of equinumerosity and dominance.
|- ((A ~~ B /\ B ~<_ C) -> A ~<_ C)
Theorem	domentr 4421	Transitivity of dominance and equinumerosity.
|- ((A ~<_ B /\ B ~~ C) -> A ~<_ C)
Theorem	f1imaen 4422	A one-to-one function's image under a subset of its domain is equinumerous to the subset.
|- C e. V   =>   |- ((F:A-1-1->B /\ C (_ A) -> (F"C) ~~ C)
Theorem	en0 4423	The empty set is equinumerous only to itself. Exercise 1 of [TakeutiZaring] p. 88.
|- (A ~~ (/) <-> A = (/))
Theorem	ensn1 4424	A singleton is equinumerous to ordinal one.
|- A e. V   =>   |- {A} ~~ 1o
Theorem	ensn1g 4425	A singleton is equinumerous to ordinal one.
|- (A e. B -> {A} ~~ 1o)
Theorem	en1 4426	A set is equinumerous to ordinal one iff it is a singleton.
|- (A ~~ 1o <-> E.x A = {x})
Theorem	2dom 4427	A set that dominates ordinal 2 has at least 2 different members.
|- A e. V   =>   |- (2o ~<_ A -> E.x e. A E.y e. A -. x = y)
Theorem	fundmen 4428	A function is equinumerous to its domain. Exercise 4 of [Suppes] p. 98.
|- F e. V   =>   |- (Fun F -> dom F ~~ F)
Theorem	mapsnen 4429	Set exponentiation to a singleton exponent is equinumerous to its base. Exercise 4.43 of [Mendelson] p. 255.
|- A e. V   &   |- B e. V   =>   |- (A ^m {B}) ~~ A
Theorem	map1 4430	Set exponentiation: ordinal 1 to any set is equinumerous to ordinal 1. Exercise 4.42(b) of [Mendelson] p. 255.
|- A e. V   =>   |- (1o ^m A) ~~ 1o
Theorem	en2sn 4431	Two singletons are equinumerous.
|- ((A e. C /\ B e. D) -> {A} ~~ {B})
Theorem	snfi 4432	A singleton is finite.
|- E.x e. om {A} ~~ x
Theorem	unen 4433	Equinumerosity of union of disjoint sets. Theorem 4 of [Suppes] p. 92.
|- (((A ~~ B /\ C ~~ D) /\ ((A i^i C) = (/) /\ (B i^i D) = (/))) -> (A u. C) ~~ (B u. D))
Theorem	xpsnen 4434	A set is equinumerous to its cross-product with a singleton. Proposition 4.22(c) of [Mendelson] p. 254.
|- A e. V   &   |- B e. V   =>   |- (A X. {B}) ~~ A
Theorem	xpsneng 4435	A set is equinumerous to its cross-product with a singleton. Proposition 4.22(c) of [Mendelson] p. 254.
|- ((A e. C /\ B e. D) -> (A X. {B}) ~~ A)
Theorem	endisj 4436	Any two sets are equinumerous to disjoint sets. Exercise 4.39 of [Mendelson] p. 255.
|- A e. V   &   |- B e. V   =>   |- E.xE.y((x ~~ A /\ y ~~ B) /\ (x i^i y) = (/))
Theorem	undom 4437	Dominance law for union. Proposition 4.24(a) of [Mendelson] p. 257.
|- B e. V   &   |- C e. V   &   |- D e. V   =>   |- (((A ~<_ B /\ C ~<_ D) /\ (B i^i D) = (/)) -> (A u. C) ~<_ (B u. D))
Theorem	xpcomen 4438	Commutative law for equinumerosity of cross product. Proposition 4.22(d) of [Mendelson] p. 254.
|- A e. V   &   |- B e. V   =>   |- (A X. B) ~~ (B X. A)
Theorem	xpcomeng 4439	Commutative law for equinumerosity of cross product. Proposition 4.22(d) of [Mendelson] p. 254.
|- ((A e. C /\ B e. D) -> (A X. B) ~~ (B X. A))
Theorem	xpassen 4440	Associative law for equinumerosity of cross product. Proposition 4.22(e) of [Mendelson] p. 254.
|- A e. V   &   |- B e. V   &   |- C e. V   =>   |- ((A X. B) X. C) ~~ (A X. (B X. C))
Theorem	xpdom2 4441	Dominance law for cross product. Proposition 10.33(2) of [TakeutiZaring] p. 92.
|- B e. V   &   |- C e. V   =>   |- (A ~<_ B -> (C X. A) ~<_ (C X. B))
Theorem	xpdom1 4442	Dominance law for cross product. Theorem 6L(c) of [Enderton] p. 149.
|- B e. V   &   |- C e. V   =>   |- (A ~<_ B -> (A X. C) ~<_ (B X. C))
Theorem	xpdom1g 4443	Dominance law for cross product. Theorem 6L(c) of [Enderton] p. 149.
|- ((B e. R /\ C e. S /\ A ~<_ B) -> (A X. C) ~<_ (B X. C))
Theorem	xpdom3 4444	A set is dominated by its cross product with a non-empty set. Exercise 6 of [Suppes] p. 98.
|- A e. V   =>   |- (B =/= (/) -> A ~<_ (A X. B))
Theorem	pw2en 4445	The power set of a set is equinumerous to set exponentiation with a base of ordinal 2. Proposition 10.44 of [TakeutiZaring] p. 96. (This proof seems excessively long. An attempt to find a shorter one is on my to-do list.)
|- A e. V   =>   |- P~A ~~ (2o ^m A)
Schroeder-Bernstein Theorem
Theorem	sbthlem1 4446	Lemma for sbth 4456.
Theorem	sbthlem2 4447	Lemma for sbth 4456.
Theorem	sbthlem3 4448	Lemma for sbth 4456.
Theorem	sbthlem4 4449	Lemma for sbth 4456.
Theorem	sbthlem5 4450	Lemma for sbth 4456.
Theorem	sbthlem6 4451	Lemma for sbth 4456.
Theorem	sbthlem7 4452	Lemma for sbth 4456.
Theorem	sbthlem8 4453	Lemma for sbth 4456.
Theorem	sbthlem9 4454	Lemma for sbth 4456.
Theorem	sbthlem10 4455	Lemma for sbth 4456.
Theorem	sbth 4456	Schroeder-Bernstein Theorem. Theorem 18 of [Suppes] p. 95. This theorem states that if set A is smaller (has lower cardinality) than B and vice-versa, then A and B are equinumerous (have the same cardinality). The interesting thing is that this can be proved without invoking the Axiom of Choice, as we do here, but the proof as you can see is quite difficult. (The theorem can be proved more easily if we allow AC.) The main proof consists of lemmas sbthlem1 4446 through sbthlem10 4455; this final piece mainly changes bound variables to eliminate the hypotheses of sbthlem10 4455. We follow closely the proof in Suppes, which you should consult to understand our proof at a higher level.
|- ((A ~<_ B /\ B ~<_ A) -> A ~~ B)
Theorem	sbthbg 4457	Schroeder-Bernstein Theorem and its converse.
|- (B e. C -> ((A ~<_ B /\ B ~<_ A) <-> A ~~ B))
Theorem	sbthcl 4458	Schroeder-Bernstein Theorem in class form.
|- ~~ = ( ~<_ i^i `' ~<_ )
Theorem	dfsdom2 4459	Alternate definition of strict dominance. Compare Definition 3 of [Suppes] p. 97.
|- ~< = ( ~<_ \ `' ~<_ )
Theorem	brsdom2 4460	Alternate definition of strict dominance. Definition 3 of [Suppes] p. 97.
|- A e. V   &   |- B e. V   =>   |- (A ~< B <-> (A ~<_ B /\ -. B ~<_ A))
Theorem	sdomnsym 4461	Strict dominance is not symmetric. Theorem 21(ii) of [Suppes] p. 97.
|- (A ~< B -> -. B ~< A)
Theorem	domnsym 4462	Theorem 22(i) of [Suppes] p. 97.
|- (A ~<_ B -> -. B ~< A)
Theorem	0dom 4463	Any set dominates the empty set.
|- (/) ~<_ A
Theorem	dom0 4464	A set dominated by the empty set is empty.
|- (A ~<_ (/) <-> A = (/))
Theorem	0sdomg 4465	A set strictly dominates the empty set iff it is not empty.
|- (A e. B -> ((/) ~< A <-> A =/= (/)))
Theorem	0sdom 4466	A set strictly dominates the empty set iff it is not empty.
|- A e. V   =>   |- ((/) ~< A <-> A =/= (/))
Theorem	sdom0 4467	The empty set does not strictly dominate any set.
|- -. A ~< (/)
Theorem	sdomdomtr 4468	Transitivity of strict dominance and dominance. Theorem 22(iii) of [Suppes] p. 97.
|- (C e. D -> ((A ~< B /\ B ~<_ C) -> A ~< C))
Theorem	sdomentr 4469	Transitivity of strict dominance and equinumerosity. Exercise 11 of [Suppes] p. 98.
|- (C e. D -> ((A ~< B /\ B ~~ C) -> A ~< C))
Theorem	ensdomtr 4470	Transitivity of equinumerosity and strict dominance.
|- ((A ~~ B /\ B ~< C) -> A ~< C)
Theorem	sdomirr 4471	Strict dominance is irreflexive. Theorem 21(i) of [Suppes] p. 97.
|- -. A ~< A
Theorem	sdomex 4472	Technical lemma for simplifying proofs involving strict dominance.
|- (A ~< B -> (A e. V /\ B e. V))
Theorem	sdomtr 4473	Strict dominance is transitive. Theorem 21(iii) of [Suppes] p. 97.
|- ((A ~< B /\ B ~< C) -> A ~< C)
Theorem	sdomn2lp 4474	Strict dominance has no 2-cycle loops.
|- -. (A ~< B /\ B ~< A)
Theorem	domsdomtr 4475	Transitivity of dominance and strict dominance. Theorem 22(ii) of [Suppes] p. 97.
|- ((A ~<_ B /\ B ~< C) -> A ~< C)
Theorem	enen1 4476	Equality-like theorem for equinumerosity.
|- ((B e. D /\ A ~~ B) -> (A ~~ C <-> B ~~ C))
Theorem	enen2 4477	Equality-like theorem for equinumerosity.
|- ((B e. D /\ A ~~ B) -> (C ~~ A <->