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Statement List for Metamath Proof Explorer - 5701-5800 - Page 58 of 108
TypeLabelDescription
Statement
 
Theoremmuln0 5701 The product of two non-zero numbers is non-zero.
|- A e. CC   &   |- B e. CC   &   |- A =/= 0   &   |- B =/= 0   =>   |- (A x. B) =/= 0
 
Theoremmuleqaddt 5702 Property of numbers whose product equals their sum. Equation 5 of [Kreyszig] p. 12.
|- ((A e. CC /\ B e. CC) -> ((A x. B) = (A + B) <-> ((A - 1) x. (B - 1)) = 1))
 
Theoremreceu 5703 Existential uniqueness of reciprocals. Theorem I.8 of [Apostol] p. 18.
|- A e. CC   &   |- B e. CC   &   |- A =/= 0   =>   |- E!x e. CC (A x. x) = B
 
Theoremmulnzcnopr 5704 Multiplication maps nonzero complex numbers to nonzero complex numbers. (Contributed by Steve Rodriguez, 23-Feb-2007.)
|- ( x. |` ((CC \ {0}) X. (CC \ {0}))):((CC \ {0}) X. (CC \ {0}))-->(CC \ {0})
 
Division
 
Definitiondf-div 5705 Define division. Theorem divmul 5707 relates it to multiplication, and divcl 5712 and redivcl 5801 prove its closure laws.
|- / = {<.<.x, y>., z>. | ((x e. CC /\ y e. (CC \ {0})) /\ z = U.{w e. CC | (y x. w) = x})}
 
Theoremdivval 5706 Value of division: the (unique) element x such that (B x. x) = A. This is meaningful only when B is nonzero.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- (A / B) = U.{x e. CC | (B x. x) = A}
 
Theoremdivmul 5707 Relationship between division and multiplication.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   &   |- B =/= 0   =>   |- ((A / B) = C <-> (B x. C) = A)
 
Theoremdivmulz 5708 Relationship between division and multiplication.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   =>   |- (B =/= 0 -> ((A / B) = C <-> (B x. C) = A))
 
Theoremdivmult 5709 Relationship between division and multiplication.
|- (((A e. CC /\ B e. CC /\ C e. CC) /\ B =/= 0) -> ((A / B) = C <-> (B x. C) = A))
 
Theoremdivmul2t 5710 Relationship between division and multiplication.
|- (((A e. CC /\ B e. CC /\ C e. CC) /\ B =/= 0) -> ((A / B) = C <-> A = (B x. C)))
 
Theoremdivmul3t 5711 Relationship between division and multiplication.
|- (((A e. CC /\ B e. CC /\ C e. CC) /\ B =/= 0) -> ((A / B) = C <-> A = (C x. B)))
 
Theoremdivcl 5712 Closure law for division.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- (A / B) e. CC
 
Theoremdivclz 5713 Closure law for division.
|- A e. CC   &   |- B e. CC   =>   |- (B =/= 0 -> (A / B) e. CC)
 
Theoremdivclt 5714 Closure law for division.
|- ((A e. CC /\ B e. CC /\ B =/= 0) -> (A / B) e. CC)
 
Theoremreccl 5715 Closure law for reciprocal.
|- A e. CC   &   |- A =/= 0   =>   |- (1 / A) e. CC
 
Theoremrecclz 5716 Closure law for reciprocal.
|- A e. CC   =>   |- (A =/= 0 -> (1 / A) e. CC)
 
Theoremrecclt 5717 Closure law for reciprocal.
|- ((A e. CC /\ A =/= 0) -> (1 / A) e. CC)
 
Theoremdivcan2 5718 A cancellation law for division.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- (B x. (A / B)) = A
 
Theoremdivcan1 5719 A cancellation law for division.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- ((A / B) x. B) = A
 
Theoremdivcan1z 5720 A cancellation law for division.
|- A e. CC   &   |- B e. CC   =>   |- (B =/= 0 -> ((A / B) x. B) = A)
 
Theoremdivcan2z 5721 A cancellation law for division. We eliminate the third hypothesis of divcan2 5718 using the weak deduction theorem dedth 2383 and keep the other two. Because the first hypothesis shares the class variable B with the hypothesis we're eliminating, we need to use keepel 2399 in order to keep the first hypothesis.
|- A e. CC   &   |- B e. CC   =>   |- (B =/= 0 -> (B x. (A / B)) = A)
 
Theoremdivcan2OLD 5722 A cancellation law for division.
|- A e. CC   &   |- B e. CC   &   |- A =/= 0   =>   |- (A x. (B / A)) = B
 
Theoremdivcan1OLD 5723 A cancellation law for division.
|- A e. CC   &   |- B e. CC   &   |- A =/= 0   =>   |- ((B / A) x. A) = B
 
Theoremdivcan1zOLD 5724 A cancellation law for division.
|- A e. CC   &   |- B e. CC   =>   |- (A =/= 0 -> ((B / A) x. A) = B)
 
Theoremdivcan2zOLD 5725 A cancellation law for division. We eliminate the third hypothesis of divcan2OLD 5722 using the weak deduction theorem dedth 2383 and keep the other two. Because the first hypothesis shares the class variable A with the hypothesis we're eliminating, we need to use keepel 2399 in order to keep the first hypothesis.
|- A e. CC   &   |- B e. CC   =>   |- (A =/= 0 -> (A x. (B / A)) = B)
 
Theoremdivcan1t 5726 A cancellation law for division.
|- ((A e. CC /\ B e. CC /\ B =/= 0) -> ((A / B) x. B) = A)
 
Theoremdivcan1tOLD 5727 A cancellation law for division.
|- ((A e. CC /\ B e. CC /\ A =/= 0) -> ((B / A) x. A) = B)
 
Theoremdivcan2t 5728 A cancellation law for division.
|- ((A e. CC /\ B e. CC /\ B =/= 0) -> (B x. (A / B)) = A)
 
Theoremdivcan2tOLD 5729 A cancellation law for division.
|- ((A e. CC /\ B e. CC /\ A =/= 0) -> (A x. (B / A)) = B)
 
Theoremdivne0bt 5730 The ratio of non-zero numbers is non-zero.
|- ((A e. CC /\ B e. CC /\ B =/= 0) -> (A =/= 0 <-> (A / B) =/= 0))
 
Theoremdivne0t 5731 The ratio of non-zero numbers is non-zero.
|- (((A e. CC /\ A =/= 0) /\ (B e. CC /\ B =/= 0)) -> (A / B) =/= 0)
 
Theoremdivne0 5732 The ratio of non-zero numbers is non-zero.
|- A e. CC   &   |- B e. CC   &   |- A =/= 0   &   |- B =/= 0   =>   |- (A / B) =/= 0
 
Theoremrecne0z 5733 The reciprocal of a non-zero number is non-zero.
|- A e. CC   =>   |- (A =/= 0 -> (1 / A) =/= 0)
 
Theoremrecne0t 5734 The reciprocal of a non-zero number is non-zero.
|- ((A e. CC /\ A =/= 0) -> (1 / A) =/= 0)
 
Theoremrecid 5735 Multiplication of a number and its reciprocal.
|- A e. CC   &   |- A =/= 0   =>   |- (A x. (1 / A)) = 1
 
Theoremrecidz 5736 Multiplication of a number and its reciprocal.
|- A e. CC   =>   |- (A =/= 0 -> (A x. (1 / A)) = 1)
 
Theoremrecidt 5737 Multiplication of a number and its reciprocal.
|- ((A e. CC /\ A =/= 0) -> (A x. (1 / A)) = 1)
 
Theoremrecid2t 5738 Multiplication of a number and its reciprocal.
|- ((A e. CC /\ A =/= 0) -> ((1 / A) x. A) = 1)
 
Theoremdivrec 5739 Relationship between division and reciprocal. Theorem I.9 of [Apostol] p. 18.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- (A / B) = (A x. (1 / B))
 
Theoremdivrecz 5740 Relationship between division and reciprocal. Theorem I.9 of [Apostol] p. 18.
|- A e. CC   &   |- B e. CC   =>   |- (B =/= 0 -> (A / B) = (A x. (1 / B)))
 
Theoremdivrect 5741 Relationship between division and reciprocal. Theorem I.9 of [Apostol] p. 18.
|- ((A e. CC /\ B e. CC /\ B =/= 0) -> (A / B) = (A x. (1 / B)))
 
Theoremdivrec2t 5742 Relationship between division and reciprocal.
|- ((A e. CC /\ B e. CC /\ B =/= 0) -> (A / B) = ((1 / B) x. A))
 
Theoremdivasst 5743 An associative law for division.
|- (((A e. CC /\ B e. CC /\ C e. CC) /\ C =/= 0) -> ((A x. B) / C) = (A x. (B / C)))
 
Theoremdiv23t 5744 A commutative/associative law for division.
|- (((A e. CC /\ B e. CC /\ C e. CC) /\ C =/= 0) -> ((A x. B) / C) = ((A / C) x. B))
 
Theoremdiv13t 5745 A commutative/associative law for division.
|- (((A e. CC /\ B e. CC /\ C e. CC) /\ B =/= 0) -> ((A / B) x. C) = ((C / B) x. A))
 
Theoremdiv12t 5746 A commutative/associative law for division.
|- (((A e. CC /\ B e. CC /\ C e. CC) /\ C =/= 0) -> (A x. (B / C)) = (B x. (A / C)))
 
Theoremdivassz 5747 An associative law for division.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   =>   |- (C =/= 0 -> ((A x. B) / C) = (A x. (B / C)))
 
Theoremdivass 5748 An associative law for division.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   &   |- C =/= 0   =>   |- ((A x. B) / C) = (A x. (B / C))
 
Theoremdivdir 5749 Distribution of division over addition.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   &   |- C =/= 0   =>   |- ((A + B) / C) = ((A / C) + (B / C))
 
Theoremdiv23 5750 A commutative/associative law for division.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   &   |- C =/= 0   =>   |- ((A x. B) / C) = ((A / C) x. B)
 
Theoremdivdirz 5751 Distribution of division over addition.
|- A e. CC