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Theorem an6 906
Description: Rearrangement of 6 conjuncts.
Assertion
Ref Expression
an6 (((φ ψ χ) (θ τ η)) ↔ ((φ θ) (ψ τ) (χ η)))

Proof of Theorem an6
StepHypRef Expression
1 df-3an 781 . . . 4 ((φ ψ χ) ↔ ((φ ψ) χ))
2 df-3an 781 . . . 4 ((θ τ η) ↔ ((θ τ) η))
31, 2anbi12i 485 . . 3 (((φ ψ χ) (θ τ η)) ↔ (((φ ψ) χ) ((θ τ) η)))
4 an4 509 . . 3 ((((φ ψ) χ) ((θ τ) η)) ↔ (((φ ψ) (θ τ)) (χ η)))
5 an4 509 . . . 4 (((φ ψ) (θ τ)) ↔ ((φ θ) (ψ τ)))
65anbi1i 484 . . 3 ((((φ ψ) (θ τ)) (χ η)) ↔ (((φ θ) (ψ τ)) (χ η)))
73, 4, 63bitri 177 . 2 (((φ ψ χ) (θ τ η)) ↔ (((φ θ) (ψ τ)) (χ η)))
8 df-3an 781 . 2 (((φ θ) (ψ τ) (χ η)) ↔ (((φ θ) (ψ τ)) (χ η)))
97, 8bitr4i 176 1 (((φ ψ χ) (θ τ η)) ↔ ((φ θ) (ψ τ) (χ η)))
Colors of variables: wff set class
Syntax hints:   ↔ wb 146   wa 223   w3a 779
This theorem is referenced by:  abfii4 4579  distrlem3pr 5149  ltdiv2 5901  elfzuzb 6444  efcltlem1 7336  iscau3 7964  iscau4 7966  infi1 10471  ficli 10492  filintf 10601  infi 10606  rcfpfillem4 10613
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7
This theorem depends on definitions:  df-bi 147  df-an 225  df-3an 781
Copyright terms: Public domain