HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Axiom ax-9o 1127
Description: A variant of ax-9 969. Axiom scheme C10' in [Megill] p. 448 (p. 16 of the preprint).

This axiom is redundant, as shown by theorem ax9o 1126.

Assertion
Ref Expression
ax-9o (x(x = yxφ) → φ)

Detailed syntax breakdown of Axiom ax-9o
StepHypRef Expression
1 vx . . . . . 6 set x
21cv 959 . . . . 5 class x
3 vy . . . . . 6 set y
43cv 959 . . . . 5 class y
52, 4wceq 960 . . . 4 wff x = y
6 wph . . . . 5 wff φ
76, 1wal 958 . . . 4 wff xφ
85, 7wi 3 . . 3 wff (x = yxφ)
98, 1wal 958 . 2 wff x(x = yxφ)
109, 6wi 3 1 wff (x(x = yxφ) → φ)
Colors of variables: wff set class
This axiom is referenced by:  ax9 1128  equid 1130  equs4 1154  equsal 1155  a4imt 1162  a4im 1163  cbv1 1166
Copyright terms: Public domain