Proof of Theorem divexpt
| Step | Hyp | Ref
| Expression |
| 1 | | divrect 5739 |
. . . . . . . 8
⊢ ((A ∈ ℂ ⋀ B ∈ ℂ ⋀ B ≠ 0) → (A / B) =
(A · (1 / B))) |
| 2 | 1 | 3expb 834 |
. . . . . . 7
⊢ ((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) → (A / B) =
(A · (1 / B))) |
| 3 | 2 | opreq1d 3975 |
. . . . . 6
⊢ ((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) → ((A / B)↑N) =
((A · (1 / B))↑N)) |
| 4 | 3 | adantr 389 |
. . . . 5
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → ((A / B)↑N) =
((A · (1 / B))↑N)) |
| 5 | | mulexpt 6594 |
. . . . . . 7
⊢ ((A ∈ ℂ ⋀ (1 /
B) ∈
ℂ ⋀
N ∈ ℕ0) → ((A · (1 / B))↑N) =
((A↑N) · ((1 / B)↑N))) |
| 6 | 5 | 3expa 833 |
. . . . . 6
⊢ (((A ∈ ℂ ⋀ (1 /
B) ∈
ℂ) ⋀
N ∈ ℕ0) → ((A · (1 / B))↑N) =
((A↑N) · ((1 / B)↑N))) |
| 7 | | recclt 5715 |
. . . . . 6
⊢ ((B ∈ ℂ ⋀ B ≠ 0) → (1 / B) ∈ ℂ) |
| 8 | 6, 7 | sylanl2 461 |
. . . . 5
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → ((A · (1 / B))↑N) =
((A↑N) · ((1 / B)↑N))) |
| 9 | | recexpt 6595 |
. . . . . . . . . 10
⊢ ((B ∈ ℂ ⋀ N ∈ ℕ0 ⋀
B ≠ 0) → ((1 / B)↑N) = (1
/ (B↑N))) |
| 10 | 9 | 3expa 833 |
. . . . . . . . 9
⊢ (((B ∈ ℂ ⋀ N ∈ ℕ0) ⋀ B ≠ 0)
→ ((1 / B)↑N) = (1 / (B↑N))) |
| 11 | 10 | an1rs 489 |
. . . . . . . 8
⊢ (((B ∈ ℂ ⋀ B ≠ 0) ⋀
N ∈ ℕ0) → ((1 / B)↑N) = (1
/ (B↑N))) |
| 12 | 11 | adantll 392 |
. . . . . . 7
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → ((1 / B)↑N) = (1
/ (B↑N))) |
| 13 | 12 | opreq2d 3976 |
. . . . . 6
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → ((A↑N)
· ((1 / B)↑N)) = ((A↑N)
· (1 / (B↑N)))) |
| 14 | | divrect 5739 |
. . . . . . 7
⊢ (((A↑N) ∈ ℂ ⋀ (B↑N) ∈ ℂ ⋀ (B↑N) ≠
0) → ((A↑N) / (B↑N)) =
((A↑N) · (1 / (B↑N)))) |
| 15 | | expclt 6581 |
. . . . . . . 8
⊢ ((A ∈ ℂ ⋀ N ∈ ℕ0) → (A↑N) ∈ ℂ) |
| 16 | 15 | adantlr 393 |
. . . . . . 7
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → (A↑N) ∈ ℂ) |
| 17 | | expclt 6581 |
. . . . . . . . 9
⊢ ((B ∈ ℂ ⋀ N ∈ ℕ0) → (B↑N) ∈ ℂ) |
| 18 | 17 | adantll 392 |
. . . . . . . 8
⊢ (((A ∈ ℂ ⋀ B ∈ ℂ) ⋀ N ∈ ℕ0) → (B↑N) ∈ ℂ) |
| 19 | 18 | adantlrr 399 |
. . . . . . 7
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → (B↑N) ∈ ℂ) |
| 20 | | expne0it 6588 |
. . . . . . . . . 10
⊢ ((B ∈ ℂ ⋀ N ∈ ℕ0 ⋀
B ≠ 0) → (B↑N) ≠
0) |
| 21 | 20 | 3expa 833 |
. . . . . . . . 9
⊢ (((B ∈ ℂ ⋀ N ∈ ℕ0) ⋀ B ≠ 0)
→ (B↑N) ≠ 0) |
| 22 | 21 | an1rs 489 |
. . . . . . . 8
⊢ (((B ∈ ℂ ⋀ B ≠ 0) ⋀
N ∈ ℕ0) → (B↑N) ≠
0) |
| 23 | 22 | adantll 392 |
. . . . . . 7
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → (B↑N) ≠
0) |
| 24 | 14, 16, 19, 23 | syl3anc 858 |
. . . . . 6
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → ((A↑N) /
(B↑N)) = ((A↑N)
· (1 / (B↑N)))) |
| 25 | 13, 24 | eqtr4d 1510 |
. . . . 5
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → ((A↑N)
· ((1 / B)↑N)) = ((A↑N) /
(B↑N))) |
| 26 | 4, 8, 25 | 3eqtrd 1511 |
. . . 4
⊢ (((A ∈ ℂ ⋀ (B ∈ ℂ ⋀ B ≠ 0)) ⋀
N ∈ ℕ0) → ((A / B)↑N) =
((A↑N) / (B↑N))) |
| 27 | 26 | exp42 383 |
. . 3
⊢ (A ∈ ℂ → (B
∈ ℂ →
(B ≠ 0 → (N ∈ ℕ0 → ((A / B)↑N) =
((A↑N) / (B↑N)))))) |
| 28 | 27 | com34 36 |
. 2
⊢ (A ∈ ℂ → (B
∈ ℂ →
(N ∈
ℕ0 → (B ≠ 0 → ((A / B)↑N) =
((A↑N) / (B↑N)))))) |
| 29 | 28 | 3imp1 846 |
1
⊢ (((A ∈ ℂ ⋀ B ∈ ℂ ⋀ N ∈ ℕ0) ⋀ B ≠ 0)
→ ((A / B)↑N) =
((A↑N) / (B↑N))) |