| Metamath Proof Explorer |
< Previous
Next >
Related theorems GIF version |
| Description: Deduction from equality to equivalence of equalities. |
| Ref | Expression |
|---|---|
| eqeq2d.1 | ⊢ (φ → A = B) |
| Ref | Expression |
|---|---|
| eqeq2d | ⊢ (φ → (C = A ↔ C = B)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | eqeq2d.1 | . 2 ⊢ (φ → A = B) | |
| 2 | eqeq2 1527 | . 2 ⊢ (A = B → (C = A ↔ C = B)) | |
| 3 | 1, 2 | syl 10 | 1 ⊢ (φ → (C = A ↔ C = B)) |